求不定積分∫e^(2√x)dx
求不定積分∫e^(2√x)dx
數(shù)學(xué)人氣：240 ℃時(shí)間：2020-03-28 19:40:13
優(yōu)質(zhì)解答
∫e^(2√x)dx令 √x=tt^2=xdx=2tdt∫e^(2t)2tdt=(1/2)∫(e^(2t))'2tdt=(1/2)(2t e^(2t)-∫e^(2t)2dt)=(1/2)(2t e^(2t)-e^(2t))=(e^(2t)/2)(2t -1)=(e^(2√x)/2)(2√x -1)
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