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  • (cosπ/8+sinπ/8)(cos^3π/8-sin^3π/8)

    (cosπ/8+sinπ/8)(cos^3π/8-sin^3π/8)
    數(shù)學(xué)人氣:754 ℃時(shí)間:2020-03-30 09:35:40
    優(yōu)質(zhì)解答
    是要化簡(jiǎn)嗎?
    (cosπ/8+sinπ/8)(cos³3π/8-sin³3π/8)
    =(cosπ/8+sinπ/8)(cosπ/8-sinπ/8)(cos²3π/8+cos3π/8sin3π/8+sin²3π/8)
    =(cos²π/8-sin²π/8)(1+1/2sin3π/4)
    =cosπ/4 × (1+1/2sin3π/4)
    (老實(shí)說(shuō)我覺(jué)得你應(yīng)該知道cosπ/4和sin3π/4的值了……)
    =cosπ/4 × (1+1/2sinπ/4)
    =√2/2 × (1+√2/4)
    =(2√2+1)/4
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