若xy=-2,x-y=52-1,則(x+1)(y-1)= _ .
若xy=-
,x-y=5
-1,則(x+1)(y-1)= ___ .
優(yōu)質(zhì)解答
原式=xy-x+y-1
=xy-(x-y)-1,
∵xy=-
,x-y=5
-1,
∴原式=-
-5
+1-1
=-6
.
故答案為:-6
.
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