a-2的絕對(duì)值+（b+1)的二次冪+c的絕對(duì)值=0
a-2的絕對(duì)值=0,（b+1)的二次冪=0,c的絕對(duì)值=0
a-2=0,b+1=0,c=0
a=2
b=-1
c=0
abc=2*(-1)*0=0啊~就這么簡(jiǎn)單啊是求詳解?。?！a-2的絕對(duì)值+（b+1)的二次冪+c的絕對(duì)值=0因?yàn)閍-2的絕對(duì)值>=0,（b+1)的二次冪>=0,c的絕對(duì)值=0所以只有當(dāng)a-2的絕對(duì)值=0,（b+1)的二次冪=0,c的絕對(duì)值=0等式才成立即a-2=0,b+1=0,c=0a=2b=-1c=0abc=2*(-1)*0=0是把a(bǔ)-2的絕對(duì)值+（b+1)這個(gè)整體開根號(hào)，是這么個(gè)意思，老師再解一遍唄，謝謝啦a-2的絕對(duì)值和（b+1)的二次冪分別為0