f'(x)=3x²-2x-1,f'(x)=0 ,3x²-2x-1=0=(3x+1)(x-1) ,x1=-1/3,x2=1
x
fx=x³-x²-x的單調(diào)區(qū)間,fx=2x+4的單調(diào)區(qū)間
fx=x³-x²-x的單調(diào)區(qū)間,fx=2x+4的單調(diào)區(qū)間
數(shù)學(xué)人氣：892 ℃時(shí)間：2020-05-10 15:40:21
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