(1+1999)×1000÷2-(2+1998)×999÷2,
=2000×1000÷2-2000×999÷2,
=1000000-999000,
=1000.
( 1+3+5+7+…+1999 )-( 2+4+6+8+…+1998 )
( 1+3+5+7+…+1999 )-( 2+4+6+8+…+1998 )
數(shù)學(xué)人氣:558 ℃時(shí)間:2020-02-02 07:22:37
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