由題意可得
f(-x)=√a*cos(-2x-θ)-sin(-2x-θ)=√a*cos(2x+θ)+sin(2x+θ)=f(x)
所以√a*cos(2x+θ)+sin(2x+θ)=√a*cos(2x-θ)-sin(2x-θ)
sin(2x+θ)+sin(2x-θ)=√a*cos(2x-θ)-√a*cos(2x+θ)
所以2sin2xcosθ=2√asin2xsinθ
因?yàn)閟in2x不等于0
所以tanθ=√a/a,又0
函數(shù)f(x)=√a*cos(2x-θ)-sin(2x-θ)(0
函數(shù)f(x)=√a*cos(2x-θ)-sin(2x-θ)(0
數(shù)學(xué)人氣：378 ℃時(shí)間：2020-04-15 20:06:36
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