開(kāi)始滑動(dòng)的臨界條件是：μmg=mw^2r,w=sqrt(μg/r)=sqrt(0.476*9.8/0.293)=4rad/s
即當(dāng)角速度w大于4rad/s時(shí)開(kāi)始滑動(dòng)
則開(kāi)始滑動(dòng)的時(shí)間t=4/0.49=8.14s
A copper block rests 29.3 cm from the center of a steel turntable.The coefficient of
A copper block rests 29.3 cm from the center of a steel turntable.The coefficient of
static friction between block and surface is
0.476.The turntable starts from rest and rotates with a constant angular acceleration of 0.49 rad/s
The acceleration of gravity is 9.8 m/s
.After what interval will the block start to
slip on the turntable?[ Hint:Ignore the tangential component of the acceleration.]
Answer in units of s
static friction between block and surface is
0.476.The turntable starts from rest and rotates with a constant angular acceleration of 0.49 rad/s
The acceleration of gravity is 9.8 m/s
.After what interval will the block start to
slip on the turntable?[ Hint:Ignore the tangential component of the acceleration.]
Answer in units of s
英語(yǔ)人氣：968 ℃時(shí)間：2020-04-06 10:06:28
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