a^2+b^2+c^2-4a-6b-10c+38
=(a²-4a+4)+(b²-6b+9)+(c²-10c+25)
=(a-2)²+(b-3)²+(c-5)²
a^2+b^2+c^2-4a-6b-10c+38
a^2+b^2+c^2-4a-6b-10c+38
數(shù)學(xué)人氣：198 ℃時間：2020-06-09 00:44:09
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