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  • 約分2X^2Y(X-Y)/12XY^2(Y-X) 通分1/a^2-3a與1/a^2-9 通分1/2x-2與1/(x-1)^2

    約分2X^2Y(X-Y)/12XY^2(Y-X) 通分1/a^2-3a與1/a^2-9 通分1/2x-2與1/(x-1)^2
    約分2X^2Y(X-Y)/12XY^2(Y-X)
    通分1/a^2-3a與1/a^2-9
    通分1/2x-2與1/(x-1)^2
    通分1/(x+1)^2與2/x^2-1與3/(x-1)(x-2)
    數(shù)學(xué)人氣:731 ℃時(shí)間:2020-04-13 11:48:19
    優(yōu)質(zhì)解答
    2X^2Y(X-Y)/12XY^2(Y-X)
    =-X/(6Y)
    1/(a^2-3a)=1/[a(a-3)]=(a+3)/[a(a-3)(a+3)]
    1/a^2-9=a/[a(a-3)(a+3)]
    1/(2x-2)=(x-1)/[2(x-1)^2]
    1/(x-1)^2=2/[2(x-1)^2]
    1/(x+1)^2=(x-1)(x-2)/[(x+1)^2(x-1)(x-2)]
    2/(x^2-1)=2(x+1)(x-2)/[(x+1)^2(x-1)(x-2)]
    3/(x-1)(x-2)=3(x+1)^2/[(x+1)^2(x-1)(x-2)]
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