積分:2/(1-u^2+2u)du
=積分:2/[-(u^2-2u+1)+2]du
=-2積分:1/[(u-1)^2-(根號(hào)2)^2]du
=-2積分:1/[(u-1)^2-(根號(hào)2)^2]d(u-1)
=-2/ln2*ln|(u-1-根號(hào)2)/(u-1+根號(hào)2)|+C
(C為常數(shù))

有公式:
積分:dx/(x^2-a^2)
=1/2aln|(x-a)/(x+a)|+C
提示:
將:1/(x^2-a^2)=1/2a*(1/(x-a)-1/(x+a))