1./z1/≤/z2/,（a^2+2^2)≤(3^2+1^2)=10,所以a^2≤6,-√6≤a≤√6.
2.選C
3.選B
1.已知復(fù)數(shù)z1=a-2i(a∈R),z2=3+i,且/z1/≤/z2/,則實(shí)數(shù)a的取值范圍
1.已知復(fù)數(shù)z1=a-2i(a∈R),z2=3+i,且/z1/≤/z2/,則實(shí)數(shù)a的取值范圍
2.已知lg9=2x,則下列各式正確的是
A.x+lg3=0 B.10^x=1/3 C.10^-X=1/3 D.10^x=9/2
3.下列函數(shù)中,周期為1的奇函數(shù)是
A.y=2sinxcosx B.y=cos2πx C.y=2sinπx D.y=2sinπxcosπx
2.已知lg9=2x,則下列各式正確的是
A.x+lg3=0 B.10^x=1/3 C.10^-X=1/3 D.10^x=9/2
3.下列函數(shù)中,周期為1的奇函數(shù)是
A.y=2sinxcosx B.y=cos2πx C.y=2sinπx D.y=2sinπxcosπx
數(shù)學(xué)人氣：362 ℃時(shí)間：2019-08-22 14:42:50
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