2H2 + O2 == 2H2O
反應(yīng)的H2和O2物質(zhì)的量之比 = 2:1
反應(yīng)的H2和O2體積之和 = 0.448 - 0.112 = 0.336L,物質(zhì)的量之和 = 0.336/22.4 = 0.015mol
所以反應(yīng)的n(H2) = 0.015*2/3 = 0.01mol,n(O2) = 0.015*1/3 = 0.005mol
其中O2全部由Na2O2與水反應(yīng)得到
2Na2O2 + 2H2O == 4NaOH + O2↑
2 1
n(Na2O2) 0.005mol
2/n(Na2O2) = 1/0.005
得n(Na2O2) = 0.01mol
生成的H2總量n(H2) = 0.112/22.4 + 0.01= 0.015mol
2Na + 2H2O == 2NaOH + H2↑
2 1
n(Na) 0.015mol
2/n(Na) = 1/0.015
得n(Na) = 0.03mol