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  • [(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]

    [(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
    數(shù)學(xué)人氣:989 ℃時(shí)間:2020-04-13 21:53:24
    優(yōu)質(zhì)解答
    [(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
    =[(1-2^-(1/32)]*[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]/[(1-2^-(1/32)]
    =[1-2^(-1)]/[(1-2^-(1/32)]
    =1/[(2-2^(31/32)]為什么這樣做,有什么方法?
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