求值 cos150 cos〔-570〕sin1110 /cos〔-420〕 sin-〔690〕
求值 cos150 cos〔-570〕sin1110 /cos〔-420〕 sin-〔690〕
數(shù)學(xué)人氣:766 ℃時間:2020-05-25 01:39:11
優(yōu)質(zhì)解答
cos150度 cos〔-570度〕sin1110度 /cos〔-420度〕 sin-〔690度〕=-cos30度cos(-2x360度+150度)sin(3x360度+30度)/cos(-360度-60度)sin(-2x360度+30度)=1/2(-cos30度)^2/(1./4)=(3/4)/(1/2)=3/2...
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