計算二次積分:∫(1,3)dx∫(2,x-1)sin(y^2)dy
計算二次積分:∫(1,3)dx∫(2,x-1)sin(y^2)dy
∫(1,3)中,1是積分下限,3是積分上限
∫(1,3)中,1是積分下限,3是積分上限
數(shù)學人氣：430 ℃時間：2020-02-04 01:32:26
優(yōu)質(zhì)解答
積分區(qū)域 D:x-1 ≤ y ≤ 2,1≤ x ≤3視為Y型區(qū)域,即：1 ≤ x ≤ y+1,0 ≤ y ≤ 2I = ∫[0,2] sin(y²)dy ∫[1,y+1] dx 交換積分次序= ∫[0,2] y sin(y²) dy = (-1/2) cos(y²) |[0,2]= 1/2﹣(1/2)cos4...
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