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  • 計(jì)算[4/(x^2-y^2)+(x+y)/(xy^2-x^2y)]除[(x+2y)(x-y)/(x^2+2xy^2)

    計(jì)算[4/(x^2-y^2)+(x+y)/(xy^2-x^2y)]除[(x+2y)(x-y)/(x^2+2xy^2)
    分式計(jì)算
    數(shù)學(xué)人氣:450 ℃時(shí)間:2019-08-22 14:33:38
    優(yōu)質(zhì)解答
    [4/(x^2-y^2)+(x+y)/(xy^2-x^2y)]除[(x+2y)(x-y)/(x^2y+2xy^2)=[4/(x-y)(x+y)+(x+y)/xy(y-x)]*xy/(x-y)=[(4xy-(x+y)^2)/xy(x+y)(x-y)]*xy/(x-y)=[-(x-y)^2]/xy(x+y)(x-y)]*xy/(x-y)=-(x-y)/xy(x+y)*xy/(x-y)=-1/(x+y)
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