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  • 1.計算 (1) (5x-2y)^2+20xy (2)(x-3)^2(x+3)^2 (3) (3x-5)^2-(2x+7)^2 (4)(x+y+1)

    1.計算 (1) (5x-2y)^2+20xy (2)(x-3)^2(x+3)^2 (3) (3x-5)^2-(2x+7)^2 (4)(x+y+1)
    1.計算 (1) (5x-2y)^2+20xy (2)(x-3)^2(x+3)^2
    (3) (3x-5)^2-(2x+7)^2 (4)(x+y+1)(x+y-1)
    (5)89.8^2 (6)47^2-94×27+27^2
    數(shù)學(xué)人氣:125 ℃時間:2019-10-18 03:04:56
    優(yōu)質(zhì)解答
    1.計算 (1) (5x-2y)^2+20xy
    =25x^2-20xy+4y^2+20xy
    =25x^2+4y^2
    (2)(x-3)^2(x+3)^2
    =(x^2-9)^2
    =x^4-18x^2+81
    (3) (3x-5)^2-(2x+7)^2
    =(3x-5+2x+7)(3x-5-2x-7)
    =(5x-2)(x-12)
    =5x^2-60x-2x+24
    =5x^2-62x+24
    (4)(x+y+1)(x+y-1)
    =(x+y)^2-1
    =x^2+2xy+y^2-1
    (5)89.8^2
    =(90-0.2)^2
    =8100-36+0.04
    =8064.04
    (6)47^2-94×27+27^2
    =(47-27)^2
    =20^2
    =400
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