a^2+b^2+2ab=8……………………1
a^2+b^2-2ab=2……………………2
1-2
4ab=6
ab=3/2
1+2
2a^2+2b^2=10
a^2+b^2=5
a^3b^3=(ab)^3=27/8
已知（a+b)(a+b)=8,(a-b)(a-b)=2,求（1）aa+bb; (2)aaabbb
已知（a+b)(a+b)=8,(a-b)(a-b)=2,求（1）aa+bb; (2)aaabbb
數(shù)學(xué)人氣：422 ℃時間：2020-03-29 06:33:36
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