在y=f(x)圖像上任取點(x0,y0),有：y0=-√3/(3^x0+√3)
(x0,y0)關(guān)于(1/2,-1/2)的對稱點為(1-x0,-1-y0)
--->-1-y0 = √3/(3^x0+√3) - 1
= (-3^x0)/(3^x0+√3)
= (-1)/[1+√3•3^(-x0)]
= (-√3)/[√3+3^(1-x0)]
= f(1-x0)
即：對稱點(1-x0,-1-y0)也在y=f(x)圖像上
--->函數(shù)y=f(x)的圖像關(guān)于點(1/2,-1/2)對稱