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  • (x-5)/(x/7)+(x-2)/(x-4)=(x-3)/(x-5)+(x-4)/(x-6)

    (x-5)/(x/7)+(x-2)/(x-4)=(x-3)/(x-5)+(x-4)/(x-6)
    數(shù)學(xué)人氣:447 ℃時間:2020-01-28 13:38:39
    優(yōu)質(zhì)解答
    (x-5)/(x-7)+(x-2)/(x-4)=(x-3)/(x-5)+(x-4)/(x-6)
    (x-7+2)/(x-7)+(x-4+2)/(x-4)=(x-5+2)/(x-5)+(x-6+2)/(x-6)
    1-2/(x-7)+1-2/(x-4)=1-2/(x-5)+1-2/(x-6)
    2/(x-7)+2/(x-4)=2/(x-5)+2/(x-6)
    1/(x-7)+1/(x-4)=1/(x-5)+1/(x-6)
    (x-4+x-7)/(x-4)(x-7)=(x-6+x-5)/(x-5)(x-6)
    (2x-11)/(x^2-11+28)=(2x-11)/(x^2-11+30)
    因為x^2-11+28不等于x^2-11+30
    分母不等,要等式成立只能分子為0
    2x-11=0
    x=11/2
    經(jīng)檢驗,x=11/2是原方程的解
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