tan(x+π/4)+tan(x-π/4)
設a=x+π/4,則x-π/4=a-π/2
原式=tana+tan(a-π/2)
=tana-cota
=sina/cosa-cosa/sina
=-2cos2a/sin2a
=-2cot2a
=-2cot(2x+π/2)
=2cot(-2x-π/2)
=2cot(π/2-2x)
=2tan2x
tan(x+π/4)+tan(x-π/4)化簡得
tan(x+π/4)+tan(x-π/4)化簡得
數(shù)學人氣：801 ℃時間：2020-06-12 07:02:01
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