(x²+4x+4/x²-6x+9 -2+ 9-6x+x²/4+4x+x²)*x²-x-6/4x²-4x+1
應該是
[(x²+4x+4)/(x²-6x+9) -2 + (9-6x+x²)/(4+4x+x²)]*(x²-x-6)/(4x²-4x+1)
= [(x+2)²/(x-3)² -2 + (x-3)²/(x+2)²]*[(x+2)(x-3)]/(2x-1)²
= [(x+2)^4 -2(x-3)²(x+2)² + (x-3)^4]/(x-3)²(x+2)²*[(x+2)(x-3)]/(2x-1)²
= [(x+2)² - (x-3)²]²/[(x-3)(x+2)]/(2x-1)²
= [5(2x-1)]² /[(x-3)(x+2)]/(2x-1)²
= 25/[(x-3)(x+2)] 【也可以寫作:25/(x²-x-6)】
如果是
[(x²+4x+4)/(x²-6x+9) -2 + (9-6x+x²)/(4+4x+x²)]*(x²-x-6)²/(4x²-4x+1)
最后結果是25【過程參考前面過程】
分式的加減!化簡
分式的加減!化簡
化簡(x^2+4x+4/x^2-6x+9 -2+ 9-6x+x^2/4+4x+x^2)*x^2-x-6/4x^2-4x+1
化簡(x^2+4x+4/x^2-6x+9 -2+ 9-6x+x^2/4+4x+x^2)*x^2-x-6/4x^2-4x+1
數(shù)學人氣:573 ℃時間:2020-06-11 21:09:37
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