已知:x-2的絕對(duì)值與(y-1)的平方互為相反數(shù)
|x-2|+(y-1)^2=0
x-2=0 y-1=0
x=2 y=1
7x的平方y(tǒng)+｛xy-【3x的平方-4（xy的平方+0.125xy）】-4x的平方y(tǒng)}
=7x^2y+｛xy-【3x^2-4xy^2-0.5xy】-4x^2y}
=7x^2y+｛xy-3x^2+4xy^2+0.5xy-4x^2y}
=7x^2y+｛-3x^2+4xy^2+1.5xy-4x^2y}
=7x^2y-3x^2+4xy^2+1.5xy-4x^2y
=3x^2y-3x^2+4xy^2+1.5xy
=3*2^2*1-3*2^2+4*2*1^2+1.5*2*1
=8+3
=11