∫dx/根號（a²-x²）^3
∫dx/根號（a²-x²）^3
數(shù)學(xué)人氣：868 ℃時間：2020-06-13 13:13:26
優(yōu)質(zhì)解答
應(yīng)該是令x=a *sinθ那么dx=a *cosθ dθ,而√(a²-x²)= a *cosθ所以原積分=∫ 1/(a *cosθ)^3 *a*cosθ dθ=∫ 1/(a *cosθ)² dθ= 1/a² *∫ 1/cos²θ dθ=1/a² * (tanθ +C),C為常數(shù)...
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