y=log2x-1分之x〔x＞1〕的反函數(shù)
由y為以2為底,x-1分之x即x/(x-1)的對數(shù),
得2^y=x/(x-1)
2^y(x-1)=x
x*(2^y)-2^y=x
x*(2^y)-x=2^y
x(2^y-1)=2^y
x=2^y/(2^y-1)
即
y=2^x/(2^x-1) (x≠0)
∴y=log2x-1分之x〔x＞1〕的反函數(shù)是:
y=2^x/(2^x-1) (x≠0).
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