m(H2O2) = 100*8% = 8g
2H2O2==2H2O+O2↑
68 36
8g X
68/8g = 36/X
X=4.24g
所以反應(yīng)后溶液中的水的質(zhì)量 = 100-8 + 4.24 = 96.24g
所以所得溶液中溶質(zhì)質(zhì)量分?jǐn)?shù) = 8/(8+96.24) = 7.7%m(H2O2) = 100*8% = 8g這一步解釋下好嗎？不好意思看錯(cuò)了，題目說(shuō)的是氫元素的質(zhì)量分?jǐn)?shù)為8%m(H2O) * 2/18 + m(H2O2) * 2/34 = 100*8%m(H2O) + m(H2O2) = 100g解得m(H2O) = 40.5g, m(H2O2) = 59.5g2H2O2==2H2O+O2↑ 68 3659.5gX68/59.5g = 36/XX=31.5g所以反應(yīng)后溶液中的水的質(zhì)量 = 40.5 + 31.5 = 72g所以所得溶液中溶質(zhì)質(zhì)量分?jǐn)?shù) = 8/(8+72) = 10%答案是40%....答案錯(cuò)了，鑒定完畢你得解釋一下啊，我不是只要答案啊，答案是10%，不是40%，你那答案有問(wèn)題。另外，提醒你一下，追問(wèn)四次后將扣財(cái)富值。