∑i^2 = 1/6 n (n+1) (2 n+1)
∑i^3 = 1/4 n^2 (n+1)^2
∑i^2 | ∑i^3 =>
(∑i^3)/(∑i^2)是整數(shù)
(∑i^3)/(∑i^2)=3(n+1)n/[2(2n+1)]=a
可是d(n+1,2n+1)=1,d(n,2n+1)=1
故2=(n+1)n,3=2n+1 => n=1
故滿足條件的n的和為1