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  • 計(jì)算:(6x^4y-10x^3Y^2+14x^2y^5)/(-2x^2y)

    計(jì)算:(6x^4y-10x^3Y^2+14x^2y^5)/(-2x^2y)
    (6x^4y-10x^3Y^2+14x^2y^5)/(-2x^2y)
    (2/3a^4b^4-1/9a^2b^3)/(-1/3ab)^2
    [3a(2a)^2-(4a)^2+8a^2/(-2a)]/(4a)
    (21x^5y^3-6x^4y^3z+3x^3y^4)/(-1/3x^3y^3)
    數(shù)學(xué)人氣:717 ℃時(shí)間:2020-06-27 09:07:47
    優(yōu)質(zhì)解答
    (6x^4y-10x^3Y^2+14x^2y^5)/(-2x^2y)
    =(2x^2y)(3x^2-5xY+7y^4)/(-2x^2y)
    =-(3x^2-5xY+7y^4)
    =-3x^2+5xY-7y^4
    (2/3a^4b^4-1/9a^2b^3)/(-1/3ab)^2
    =[1/9(ab)^2](6a^2b^2-b)/[1/9(ab)^2]
    =6a^2b^2-b
    [3a(2a)^2-(4a)^2+8a^2/(-2a)]/(4a)
    =(3a×4a^2-16a^2-4a)/(4a)
    =4a×(3a^2-4a-1)/(4a)
    =3a^2-4a-1
    (21x^5y^3-6x^4y^3z+3x^3y^4)/(-1/3x^3y^3)
    =x^3y^3(21x^2-6xz+3y)/(-1/3x^3y^3)
    =(21x^2-6xz+3y)×x^3y^3/(-1/3x^3y^3)
    =-(21x^2-6xz+3y)×3
    =-63x^2+18xz-9y
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