y=2x^2+(1-2m)x-m+3是偶函數(shù)
所以
y=2x^2+(1-2m)x-m+3≡2x^2-(1-2m)x-m+3
即
2(1-2m)x≡0
1-2m=0
m=1/2
即
y=2x^2-1/2+3
=2x^2+5/2
頂點(diǎn)為（0.,5/2）
y=2x^2+(1-2m)x-m+3是偶函數(shù),則該函數(shù)圖像的頂點(diǎn)坐標(biāo)為
y=2x^2+(1-2m)x-m+3是偶函數(shù),則該函數(shù)圖像的頂點(diǎn)坐標(biāo)為
數(shù)學(xué)人氣：118 ℃時(shí)間：2020-03-29 06:08:14
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