由題設(shè)x=(根號(hào)8-根號(hào)7)/(根號(hào)8+根號(hào)7) y=(根號(hào)8+根號(hào)7)/(根號(hào)8-根號(hào)7) ,知:
x=(根號(hào)8-根號(hào)7)/(根號(hào)8+根號(hào)7)
=(根號(hào)8-根號(hào)7)的平方/((根號(hào)8+根號(hào)7)(根號(hào)8-根號(hào)7))
=(8+7-2根號(hào)(8*7)/(8-1)
=15-2根號(hào)(8*7)
y=(根號(hào)8+根號(hào)7)/(根號(hào)8-根號(hào)7)
=(根號(hào)8+根號(hào)7)的平方/((根號(hào)8+根號(hào)7)(根號(hào)8-根號(hào)7))
=(8+7+2根號(hào)(8*7)/(8-1)
=15+2根號(hào)(8*7)
則:(x+y+2根號(hào)(xy))/(根號(hào)x+根號(hào)y)
=(根號(hào)x+根號(hào)y)的平方/(根號(hào)x+根號(hào)y)
=根號(hào)x+根號(hào)y
=根號(hào)(15-2根號(hào)(8*7))+根號(hào)(15+2根號(hào)(8*7))>0
因此:
((x+y+2根號(hào)(xy))/(根號(hào)x+根號(hào)y) )的平方
=(15-2根號(hào)(8*7))+(15+2根號(hào)(8*7))+2根號(hào)((15-2根號(hào)(8*7))(15+2根號(hào)(8*7)))
=30+2根號(hào)(15*15-2*2*(8*7))
=30+2根號(hào)(225-224)
=32
故:
(x+y+2根號(hào)(xy))/(根號(hào)x+根號(hào)y)
=根號(hào)32
=4根號(hào)2
已知:x=(根號(hào)8-根號(hào)7)/(根號(hào)8+根號(hào)7) y=(根號(hào)8+根號(hào)7)/(根號(hào)8-根號(hào)7) 求:(x+y+2根號(hào)(xy))/(根號(hào)x+根號(hào)y)
已知:x=(根號(hào)8-根號(hào)7)/(根號(hào)8+根號(hào)7) y=(根號(hào)8+根號(hào)7)/(根號(hào)8-根號(hào)7) 求:(x+y+2根號(hào)(xy))/(根號(hào)x+根號(hào)y)
數(shù)學(xué)人氣:165 ℃時(shí)間:2019-10-19 21:34:21
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