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  • 分解因式:

    分解因式:
    2m^3 - 8m
    (x+2)(x+4)+ x^2 -4
    4(x-y)^2 - 2(y-x)^3
    x^2 (y^2 - 1)+2x(y^2 - 1)+(y^2 - 1)
    a(x-y)-b(y-x)+c(x-y)
    3 x^3 y - 6xy + 3y
    x^3 + 6x^2 - 27
    b^2 - 2b
    a^3-ab^2
    x^3-6x^2+9x
    (2a-b)^2 + 8ab
    (x+2)(x+3)+ x^2 + 4
    xy-x-y+1
    a^2 - b^2 + 4b
    a^2 - 2ab + b^2 -1
    計(jì)算:
    [1-1/(2^2)][1-1/(3^2)]...[1-1/(9^2)][1-1/(10^2)]
    2010^2 - 2009^2 + 2008^2 - 2007^2 +...+ 2^2 - 1^2
    27^2-46*27+ 23^2
    若a^2 + b^2 + 2a-4b+5=0,求實(shí)數(shù)a,b的值.
    若非零實(shí)數(shù)a,b滿足 4a^2 + b^2 =4ab,則b/a=
    數(shù)學(xué)人氣:138 ℃時(shí)間:2020-01-31 11:21:59
    優(yōu)質(zhì)解答
    1.2m^3 - 8m =2m(m^2-4)=2m(m-2)(m+2)
    2.(x+2)(x+4)+ x^2 -4
    =(x+2)(x+4)+(x-2)(x+2)
    =(x+2)(2x+2)=2(x+2)(x+1)
    3.4(x-y)^2 - 2(y-x)^3 =
    4(x-y)^2 +2(x-y)^3=
    (x-y)^2(4+2x-2y)
    4.x^2 (y^2 - 1)+2x(y^2 - 1)+(y^2 - 1)=
    (y^2 - 1)(x^2+2x+1)=(y^2 - 1)(x+1)^2
    a(x-y)-b(y-x)+c(x-y)
    =a(x-y)+b(x-y)+c(x-y)
    =(x-y)(a+b+c
    3 x^3 y - 6xy + 3y
    =3y(x^3 - 2x + 1)
    =3y(x^3 - x^2+ x^2 -2x + 1)
    =3y(x-1)(x^2+x-1)
    x^3 + 6x^2 - 27
    =X立+3X方+(3X方-27)
    =X方(X+3)+3(X+3)(X-3)
    2a-b)^2+8ab
    (2a-b)^2+8ab=4a^2-4ab+b^2+8ab
    =4a^2+4ab+b^2
    =(2a+b)^2
    (x+2)(x+3)+ x^2 +4=X方+5X+6+X方+4
    =2X方+5X+4
    =(X+2)(2X+2)
    xy-x-y+1
    =x(y-1)-(y-1)
    =(x-1)(y-1)
    =(X+3)(X方+3X-9)
    a^2 - 2ab + b^2 -1=(A-B)方-1
    =(A-B+1)(A-B-1)
    計(jì)算:(1-1/2^2)=(1-1/2)(1+1/2)=1/2*3/2
    (1-1/3^2)=(1-1/3)(1+1/3)=2/3*4/3
    ...
    (1-1/9^2)=8/9*10/9
    (1-1/10^2)=9/10*11/10
    (1-1/2^2)(1-1/3^2)(1-1/4^2)...(1-1/9^2)(1-1/10^2)
    =1/2*3/2*2/3*4/3*...*8/9*10/9*9/10*11/10
    =1/2*11/10
    =11/20
    2010^2 - 2009^2 + 2008^2 - 2007^2 +...+ 2^2 - 1^2=2011(2010-2009+2008_2007+...+2-1)=2011*1005=2021055
    27^2-46*27+ 23^2
    =27^2-2*23*27+ 23^2
    =(27-23)^2=25
    a^2 + b^2 + 2a-4b+5
    =(a^2+ 2a+1)+( b^2-4b+4)
    =(a+1)^2+(b-2)^2=0
    a+1=0 b-2=0
    a=-1 b=2
    4a^2 + b^2 =4ab
    4a^2 + b^2 -4ab=0 兩邊通除以非負(fù)數(shù)a^2
    (b/a)^2-4b/a+4=0 b/a=2
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