原式=(cosx)^2/[(-cosx)/sinx]
=-sinxcosx
=-1/2*sin2x
數(shù)學涵數(shù)化簡
數(shù)學涵數(shù)化簡
(1+cos2X)/(tanX/2-cotX/2) 化簡
(1+cos2X)/(tanX/2-cotX/2) 化簡
數(shù)學人氣：555 ℃時間：2020-06-02 03:41:23
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