精品偷拍一区二区三区,亚洲精品永久 码,亚洲综合日韩精品欧美国产,亚洲国产日韩a在线亚洲

  • <center id="usuqs"></center>
  • 
    
  • 定積分∫(上限π/3,下限π/4)x/(sin^2x)dx

    定積分∫(上限π/3,下限π/4)x/(sin^2x)dx
    數(shù)學人氣:116 ℃時間:2020-02-05 17:31:29
    優(yōu)質(zhì)解答
    原式=∫x*csc^2x dx(下限π/4,上限π/3)
    =-(1/2)*∫xd(cot2x)(下限π/4,上限π/3)
    =-(1/2)*xcot2x+(1/2)*∫cot2xdx(下限π/4,上限π/3)
    =-(1/2)*(π/3)*cot(2π/3)+(1/4)*∫(cos2x/sin2x)d(2x)(下限π/4,上限π/3)
    =√3π/18+(1/4)*∫d(sin2x)/sin2x(下限π/4,上限π/3)
    =√3π/18+(1/4)*ln|sin2x|(下限π/4,上限π/3)
    =√3π/18+(1/4)*ln(√3/2)=√3π/18+(ln3)/8-(ln2)/4
    我來回答
    類似推薦
    請使用1024x768 IE6.0或更高版本瀏覽器瀏覽本站點,以保證最佳閱讀效果。本頁提供作業(yè)小助手,一起搜作業(yè)以及作業(yè)好幫手最新版!
    版權(quán)所有 CopyRight © 2012-2024 作業(yè)小助手 All Rights Reserved. 手機版