對(duì)質(zhì)量為m1的物體受力分析并合成如圖:由平衡條件得:F′=m1g
![](http://hiphotos.baidu.com/zhidao/pic/item/2f738bd4b31c8701e3614954247f9e2f0608ffa9.jpg)
因?yàn)榻铅潦?0°,所以三角形為等邊三角形,畫(huà)出來(lái)的平行四邊形為菱形,根據(jù)對(duì)稱(chēng)性可知支持力和拉力大小相等
連接菱形對(duì)角線,對(duì)角線相互垂直,紅色三角形為直角三角形:
由三角函數(shù)關(guān)系:
sinα=
| ||
T |
| ||
T |
m1g |
2m2g |
由α=60°
即:
m1g |
2m2g |
| ||
2 |
得:
m2 |
m1 |
| ||
3 |
故答案為:
| ||
3 |
m2 |
m1 |
| ||
T |
| ||
T |
m1g |
2m2g |
m1g |
2m2g |
| ||
2 |
m2 |
m1 |
| ||
3 |
| ||
3 |