在實(shí)數(shù)范圍內(nèi)分解因式x2y-2xy-y=_.
在實(shí)數(shù)范圍內(nèi)分解因式x2y-2xy-y=______.
優(yōu)質(zhì)解答
x
2y-2xy-y=y(x
2-2x-1)
=y(x
2-2x+1-2)=y[(x-1)
2-
()2]
=y(x-1+
)(x-1-
),
故答案為:y(x-1+
)(x-1-
).
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