the solution：
y=Asinh （mx）+Bcosh （mx）
so-----y'=mAcosh（mx）+mBsinh（mx）
so-----y''=m^2Asinh mx+m^2Bcosh mx=m^2(Asinh mx+Bcosh mx)=ym^2
Do you understand?
show that any function of the form y=Asin(mx)+Bcosh(mx) satisfies the differential equation y''=m^2y
show that any function of the form y=Asin(mx)+Bcosh(mx) satisfies the differential equation y''=m^2y
show that any function of the form y=Asinh(mx)+Bcosh(mx) satisfies the differential equation y''=m^2y
是這個
show that any function of the form y=Asinh(mx)+Bcosh(mx) satisfies the differential equation y''=m^2y
是這個
數(shù)學(xué)人氣：873 ℃時間：2020-05-08 20:40:37
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