sin3α=sin(2α+α)=sin2αcosα+cos2αsinα
=2sinα(cosα)^2+(1-2(sinα)^2)sinα
=2sinα[1-(sinα)^2]+(1-2(sinα)^2)sinα
=2sinα-2(sinα)^3+sinα-2(sinα)^3
=3sinα-4(sinα)^3
sin（2×18°）＝cos（3×18°）
2sin18°cos18°＝4(cos18°)^3－3cos18°
∵cos18°≠0
∴2sin18°＝4(cos18°)^2－3
整理得4(sin18°)＾2＋2sin18°－1＝0
解得sin18°＝（根號5－1）/4
通過sin30°,求得sin15°,通過sin18°,sin15°,求得sin3°