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整理得:x2-5x+6=0
解得:x=2或x=3
答:2或3秒后△PBQ的面積等于6cm2
(2)當PQ=5時,在Rt△PBQ中,∵BP2+BQ2=PQ2,
∴(5-t)2+(2t)2=52,
5t2-10t=0,
t(5t-10)=0,
t1=0,t2=2,
∵t=0時不合題意,舍去,
∴當t=2時,PQ的長度等于5cm.
(3)設經(jīng)過x秒以后△PBQ面積為8,
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整理得:x2-5x+8=0
△=25-32=-7<0
∴△PQB的面積不能等于8cm2.
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