A = magic(10);
A(1,:)表示第一行,A(2,:)表示第二行,...,依次類推
A(:,1)表示第一列,A(:,2)表示第二列,...,依次類推
diag(A)表示主對角線的元素
diag(fliplr(A))表示副對角線的元素
sum函數(shù)用來求和,比如
sum(A(1,:)) 返回的就是矩陣第一行元素之和,依次類推
至于最后一問：
[rows,cols,vals] = find( 40，我不是計算機專業(yè)的學生只是選修課要求做請您能不能直接把程序寫給我呀，非常感謝啦A = magic(10);%求所有行元素之和SumH1 = sum(A(1,:)) ; %第一行SumH2 = sum(A(2,:)) ; SumH3 = sum(A(3,:)) ; SumH4 = sum(A(4,:)) ; SumH5 = sum(A(5,:)) ; SumH6 = sum(A(6,:)) ; SumH7 = sum(A(7,:)) ; SumH8 = sum(A(8,:)) ; SumH9 = sum(A(9,:)) ; SumH10 = sum(A(10,:)) ; %第十行%求所有列元素之和SumL1 = sum(A(:,1)) ; %第一列SumL2 = sum(A(:,2)) ;SumL3 = sum(A(:,3)) ;SumL4 = sum(A(:,4)) ;SumL5 = sum(A(:,5)) ;SumL6 = sum(A(:,6)) ;SumL7 = sum(A(:,7)) ;SumL8 = sum(A(:,8)) ;SumL9 = sum(A(:,9)) ;SumL10 = sum(A(:,10)) ; %第十列%求主對角線元素之和SumZ = sum(diag(A));%求副對角線元素之和SumZ = sum(diag(fliplr(A)));%將矩陣中大于40，小于60的數(shù)用NaN代替[rows,cols,vals] = find( 40