![](http://hiphotos.baidu.com/zhidao/pic/item/faedab64034f78f0de0d65427a310a55b3191c78.jpg)
∴BD=
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
①如圖1,點C在AB的延長線上時,DE=BD+BE=2+3=5cm,
∵點F是線段DE的中點,
∴EF=
1 |
2 |
1 |
2 |
5 |
2 |
此時,BF=BE-EF=3-
5 |
2 |
1 |
2 |
②如圖2,點C在AB的反向延長線上時,DE=BE-BD=3-2=1cm,
∵點F是線段DE的中點,
∴EF=
1 |
2 |
1 |
2 |
1 |
2 |
此時,BF=BE-EF=3-
1 |
2 |
5 |
2 |
綜上所述,BF=
1 |
2 |
5 |
2 |
故答案為:
1 |
2 |
5 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
5 |
2 |
5 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
5 |
2 |
1 |
2 |
5 |
2 |
1 |
2 |
5 |
2 |