大家都寫錯了,我的才對,
翻譯：所給的關(guān)于x的不等式的整數(shù)解是1,2,3.,那么由整數(shù)a跟b組成的組合有幾個?
由[3(x-a)+2≥2(1-2x-a)] 得x≥ a/7
由[(x+b)÷3＜(b-x)÷2] 得x＜b/5
所以a/7≤x＜b/5
因為x的不等式的整數(shù)解是1,2,3
所以1≥a/7>0,解得7≥a>0,a可以取7,6,5,4,3,2,1,共7種可能
3
英語數(shù)學(xué)題：
英語數(shù)學(xué)題：
The integer solutions of the inequalities about"x" [3(x-a)+2≥2(1-2x-a)] and [(x+b)÷3＜(b-x)÷2] are 1,2,3,then the number of integer pairs (a,b) is ( )
先翻譯
The integer solutions of the inequalities about"x" [3(x-a)+2≥2(1-2x-a)] and [(x+b)÷3＜(b-x)÷2] are 1,2,3,then the number of integer pairs (a,b) is ( )
先翻譯
數(shù)學(xué)人氣：734 ℃時間：2020-02-02 11:10:33
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