x+8 |
(x?2)2 |
x(x?2) |
x+3 |
1 |
x?2 |
x(x?2) |
x+3 |
x(x+8) |
(x?2)(x+3) |
x(x?2) |
(x?2)(x+3) |
2x(x+3) |
(x?2)(x+3) |
2x |
x?2 |
方程x2-4=0,解得:x=2或-2,
當(dāng)x=2時(shí),原式?jīng)]有意義,舍去,
則當(dāng)x=-2時(shí),原式=1.
x+8 |
x2?4x+4 |
1 |
2?x |
x+3 |
x2?2x |
x+8 |
(x?2)2 |
x(x?2) |
x+3 |
1 |
x?2 |
x(x?2) |
x+3 |
x(x+8) |
(x?2)(x+3) |
x(x?2) |
(x?2)(x+3) |
2x(x+3) |
(x?2)(x+3) |
2x |
x?2 |