則,a+b=0 cd=1
若ab互為相反數(shù),cd互為倒數(shù),m的絕對(duì)值為2
則,a+b=0 cd=1,m=2,(-2)
當(dāng)m=2
a+b/a+b+m +m的平方-cd
=0/(0+2)+2^2-1=3
當(dāng)m=-2
a+b/a+b+m +m的平方-cd
=0/(0-2)+(-2)^2-1=4-1
=3
若ab互為相反數(shù),cd互為倒數(shù),m的絕對(duì)值為2
則,a+b=0 cd=1,m=2,(-2)
當(dāng)m=2
a+b/a+b+m +m的平方-cd
=0/(0+2)+2^2-1
=3
當(dāng)m=-2
a+b/a+b+m +m的平方-cd
=0/(0-2)+(-2)^2-1
=4-1
=3