已知mn=-1,m-n=4
則
(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)
=-2mn+m+n-3mn-5n+5m-m-4n+3mn
=-2mn+5m-8n
=2+20-3n
=22-3n
又n=-2+/-sqrt(3)
所以,原式=28-3*sqrt(3)或28+3*sqrt(3)
若m-n=4,mn=-1,求(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)的值
若m-n=4,mn=-1,求(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)的值
數(shù)學(xué)人氣：169 ℃時(shí)間：2020-02-05 08:16:15
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