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    1
    use the factor therem to factorise the following cubics as far as possible:
    f(x)=x(的三次方)-7x+6
    2
    find a given that (x+4) is a factor of f(x)=x(的三次方)+8x^+ax+12 and hence factorise f(x) completely.
    3
    show that (x-2) is a factor of f(x)=x的三次方-4x^+x+6 and hence solve f(x)=0.
    4
    find the three solutions to each of the following equations
    10x的三次方-29x^+25x-6=0
    5
    the expression ax^+bx+6 has remainder 15 when divided by (x-1) and remainder 1 when divided by (x+1).find the values of a and b.
    6
    given that (x^-1)is a factor of x的三次方+ax^+bx -4 ,find the values of a and b
    英語人氣:494 ℃時間:2020-04-06 07:39:59
    優(yōu)質解答
    -5/2(a-3)除以16/a-3+(a+3) a-5/2(a-3)除以16/a-3+(a+3)(a-3)/(a-3) a-5/2(a-3)除以(16+a^2-9)/(a-3) a-5/2(a-3)除以(7+a^2)/(a-3) a-5/2(a-3))乘以(a-3)/(7+a^2) (a-5)/ 2(7+a^2)
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