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  • 計(jì)算x/(x^2-1) + (x^-x+1)/(x^3-x^2+x-1)+(x^2+x+1)/(x^3+x^2+x+1)-2x^3/(x^4-1)

    計(jì)算x/(x^2-1) + (x^-x+1)/(x^3-x^2+x-1)+(x^2+x+1)/(x^3+x^2+x+1)-2x^3/(x^4-1)
    數(shù)學(xué)人氣:825 ℃時(shí)間:2020-03-19 16:04:10
    優(yōu)質(zhì)解答
    x/(x^2-1) + (x^2-x+1)/(x^3-x^2+x-1)+(x^2+x+1)/(x^3+x^2+x+1)-2x^3/(x^4-1)
    =x/(x^2-1) -2x^3/(x^4-1) + (x^2-x+1)/(x^3-x^2+x-1)+(x^2+x+1)/(x^3+x^2+x+1)
    =x*(x^2+1) /(x^4-1) -2x^3/(x^4-1)+ (x^2-x+1)/[(x-1)*(x^2 +1)]+ (x^2+x+1)/[(x+1)*(x^2+1)]
    =(x^3-2x^3+x) / (x^4-1) + [(x^2-x+1)*(x+1)+ (x^2+x+1)*(x-1)] /[(x-1)*(x+1)*(x^2+1)]
    =(-x^3+x) / (x^4-1) + 2x^3/(x^4 -1)
    =(x^3+x) / (x^4-1)
    =x*(x^2+1) / (x^4-1)
    = x/(x^2-1)
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