1+tanx |
1?tanx |
則
1 |
cos2x |
1 |
cos2x |
sin2x |
cos2x |
1+sin2x |
cos2x |
(sinx+cosx)2 |
cos2x?sin2x |
=
cosx+sinx |
cosx?sinx |
1+tanx |
1?tanx |
故答案為:2010
1+tanx |
1?tanx |
1 |
cos2x |
1+tanx |
1?tanx |
1 |
cos2x |
1 |
cos2x |
sin2x |
cos2x |
1+sin2x |
cos2x |
(sinx+cosx)2 |
cos2x?sin2x |
cosx+sinx |
cosx?sinx |
1+tanx |
1?tanx |