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  • 分式加減法 急.求

    分式加減法 急.求
    1.(4a/a-2-a/a+2)÷1/a^2-4
    2.[(a-1/a^2-4a+4)-(a+2/a^2-2a)]÷(4/a-1)
    3.(1/a-1)-(2/1-a^2)
    4.(a+b/ab)-(b+c/bc)
    5.[3x/(x-3)^2]-(x/3-x)
    6.(x-2)-(x^2/x+2)
    7.(2x/x^2-4)-(1/x-2)
    急...........求求你們了
    數(shù)學人氣:834 ℃時間:2020-01-29 08:17:32
    優(yōu)質(zhì)解答
    1.(4a/a-2-a/a+2)÷1/a^2-4=〔4a(a+2)/(a-2)(a+2)-a(a-2)/(a-2)(a+2)〕*(a+2)(a-2)
    =(3a^2+10a)/(a-2)(a+2))〕*(a+2)(a-2)
    =3a^2+10a
    2.[(a-1/a^2-4a+4)-(a+2/a^2-2a)]÷(4/a-1)=〔a(a-1)/a(a-2)^2-(a^2-4)/a(a-2)^2〕*a/4-a
    =〔(4-a)/a(a-2)^2〕*a/4-a
    =1/(a-2)^2
    3.(1/a-1)-(2/1-a^2)=1/(a-1)+2/(a^2-1)
    =(a+1)/(a^2-1)+2/(a^2-1)
    =(a+3)/(a^2-1)
    4.(a+b/ab)-(b+c/bc)=c(a+b)/abc-a(b+c)/abc
    =b(c-a)/abc
    =(c-a)/ac
    5.[3x/(x-3)^2]-(x/3-x)=3x/(3-x)^2-(x/3-x)
    = 3x-x(3-x)/(3-x)^2
    =x^2/(3-x)^2
    6.(x-2)-(x^2/x+2)=(x-2)(x+2)/(x+2)-(x^2/x+2)
    =x^2-4-x^2/(x+2)
    =-4/(x+2)
    7.(2x/x^2-4)-(1/x-2)=2x/(x-2)(x+2)-(x+2)/(x-2)(x+2)
    =(x-2)/(x-2)(x+2)
    =1/(x+2)
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