平方寫好一點,我還以為是x2只是一個變量.
答案應(yīng)該是原點（0,0,0）.
x^2+y^2+z^2=1 是個半徑為1的小球,中心座落在原點.
x^2+y^2+z^2=9 是個半徑為3的稍微大點的球,中心也是座落在原點.
靠觀察就知道兩球之間的solid的中心也是在原點.
你也可以用微積分做,我懶得去做了.如果你微積分好的話,這題不難.用spherical coordination去做,不要用cartesian coordination.做法是每個點的moment總和 除以 每個點mass的總和.要做三次,每一次計算moment跟據(jù)一個axis.
求解Find the center of mass of the solid between the spheres x2 + y2 + z2 = 1 and
求解Find the center of mass of the solid between the spheres x2 + y2 + z2 = 1 and
Find the center of mass of the solid between the spheres x2 + y2 + z2 = 1 and
x2 + y2 + z2 = 9 if the density is proportional to the distance from the origin.
Find the center of mass of the solid between the spheres x2 + y2 + z2 = 1 and
x2 + y2 + z2 = 9 if the density is proportional to the distance from the origin.
數(shù)學(xué)人氣：850 ℃時間：2020-06-08 07:36:34
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